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Filtration
Removal of suspended solids through granular media or membrane filters
Overview
Tertiary filtration removes residual TSS after secondary treatment, achieving <5 mg/L TSS and <2 NTU turbidity. Types include rapid sand filters, dual-media filters, continuous backwash filters, and disk/cloth filters. Essential for disinfection effectiveness and water reuse applications.
Theory - Basic Mode
$$\text{TSS}{out} = \text{TSS}$$ $$\text{Turbidity}{out} = \text{Turbidity}$$
Typical performance:
- Rapid sand: TSS <5 mg/L, Turb <2 NTU
- Dual-media: TSS ❤️ mg/L, Turb <1 NTU
- Cloth disk: TSS <5 mg/L
- Membrane: TSS <0.1 mg/L
Theory - Advanced Mode
Carmen-Kozeny Headloss:
$$h = \frac{k \times \mu \times v \times L}{g \times d^2 \times \epsilon^3} \times (1-\epsilon)^2$$
Where:
- h = headloss (m)
- k = shape factor (~5)
- μ = viscosity
- v = filtration rate (m/h)
- L = bed depth (m)
- d = media diameter (m)
- ε = porosity (0.40-0.45)
Filtration Rate:
$$q = \frac{Q}{A}$$
Typical rates: 5-15 m/h (gravity), 10-30 m/h (pressure)
Parameters
| Filter Type | Rate | Depth | Media | TSS Out |
|---|---|---|---|---|
| Rapid Sand | 5-10 | 0.6-1.0 | 0.5-1.0 mm sand | <5 mg/L |
| Dual Media | 10-20 | 0.6-0.9 | Sand + anthracite | ❤️ mg/L |
| Continuous | 5-10 | 0.6-1.2 | Sand | <5 mg/L |
| Cloth Disk | - | - | 10-20 μm | <5 mg/L |
Worked Example
Given: Dual-media filter for 15,000 m³/d Calculate: Filter area
- Design rate: 12 m/h
- Area required: 15,000 / 24 / 12 = 52 m²
- Use 4 filters × 15 m² = 60 m² (allows 1 out for backwash)
References
- Metcalf & Eddy (2014)
- AWWA (2011). Water Treatment Plant Design