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Primary Clarifier ​

Gravity settling for removal of settleable solids from raw wastewater

Overview ​

Primary clarifiers are sedimentation tanks that remove suspended solids and associated organic matter from raw wastewater through gravity settling. They typically achieve 50-70% removal of total suspended solids (TSS) and 25-40% removal of biochemical oxygen demand (BOD5). Primary clarifiers are an essential component of conventional wastewater treatment, reducing the organic and solids loading to downstream biological treatment processes.

The process relies on the principle that particles denser than water will settle under quiescent conditions. Primary clarifiers are designed to provide sufficient detention time (typically 1.5-2.5 hours) and low surface overflow rates (30-50 m³/m²/day) to allow settleable solids to accumulate at the tank bottom. The clarified effluent overflows weirs at the tank perimeter, while settled sludge is collected by mechanical scrapers and pumped to sludge processing facilities.

Primary clarifiers can be circular (10-60m diameter) or rectangular (15-90m long) in configuration. Circular tanks use rotating sludge collectors, while rectangular tanks employ chain-and-flight scrapers. The concentrated primary sludge typically contains 2-6% solids and includes both organic and inorganic materials.

Theory and Equations ​

Basic Mode ​

Simple efficiency-based removal using empirical removal percentages:

$$\text{TSS}{out} = \text{TSS} \times (1 - \eta_{TSS})$$

$$\text{BOD}{out} = \text{BOD} \times (1 - \eta_{BOD})$$

$$\text{COD}{out} = \text{COD} \times (1 - \eta_{COD})$$

$$\text{TP}{out} = \text{TP} \times (1 - \eta_{TP})$$

$$\text{TKN}{out} = \text{TKN} \times (1 - \eta_{TKN})$$

Where:

  • $\eta_{TSS}$ = TSS removal efficiency (typically 0.50-0.70)
  • $\eta_{BOD}$ = BOD removal efficiency (typically 0.25-0.40)
  • $\eta_{COD}$ = COD removal efficiency (typically 0.25-0.40)
  • $\eta_{TP}$ = Total phosphorus removal efficiency (typically 0.05-0.15)
  • $\eta_{TKN}$ = Total Kjeldahl nitrogen removal efficiency (typically 0.10-0.20)

Sludge Production:

$$\text{Sludge mass} = Q \times (\text{TSS}{in} - \text{TSS})$$

$$\text{Sludge volume} = \frac{\text{Sludge mass}}{\rho \times C_{sludge}}$$

Where:

  • $Q$ = flow rate (m³/d)
  • $\rho$ = sludge density (≈ 1000 kg/m³)
  • $C_{sludge}$ = sludge concentration (typically 0.02-0.06, or 2-6%)

Advanced Mode ​

Overflow Rate Method (Ideal Settling):

The removal efficiency based on Stokes' Law settling velocity:

$$\eta = 1 - \exp\left(-\frac{v_s \cdot A}{Q}\right)$$

Where:

  • $v_s$ = particle settling velocity (m/h)
  • $A$ = surface area (m²)
  • $Q$ = flow rate (m³/h)

Stokes' Law Settling Velocity:

$$v_s = \frac{g \cdot d_p^2 \cdot (\rho_p - \rho_w)}{18 \cdot \mu}$$

Where:

  • $g$ = gravitational acceleration (9.81 m/s²)
  • $d_p$ = particle diameter (m)
  • $\rho_p$ = particle density (kg/m³)
  • $\rho_w$ = water density (kg/m³)
  • $\mu$ = dynamic viscosity (Pa·s)

Camp-Hazen Fraction Removed:

For a distribution of particle sizes:

$$\eta = \frac{1}{v_{s0}} \int_0^{v_{s0}} f(v_s) , dv_s + \int_{v_{s0}}^{\infty} \frac{v_{s0}}{v_s} f(v_s) , dv_s$$

Where:

  • $v_{s0}$ = overflow rate = $Q/A$ (m/h)
  • $f(v_s)$ = probability density function of settling velocities

Takács Settling Model (for hindered settling):

$$v_s(X) = v_0 \cdot \exp(-r_h \cdot X) - v_0' \cdot \exp(-r_p \cdot X)$$

Where:

  • $v_0$ = maximum settling velocity (m/h)
  • $v_0'$ = maximum rising velocity (m/h)
  • $r_h$ = hindered settling parameter (L/g)
  • $r_p$ = flocculent settling parameter (L/g)
  • $X$ = solids concentration (g/L)

Model Parameters ​

Basic Mode Parameters ​

ParameterSymbolUnitDefaultRangeDescription
TSS Removalη_TSS-0.600.50-0.70TSS removal efficiency
BOD Removalη_BOD-0.300.25-0.40BOD removal efficiency
COD Removalη_COD-0.300.25-0.40COD removal efficiency
TP Removalη_TP-0.100.05-0.15Total phosphorus removal efficiency
TKN Removalη_TKN-0.150.10-0.20Total Kjeldahl nitrogen removal
Sludge ConcentrationC_s%4.02.0-6.0Primary sludge solids concentration

Advanced Mode Parameters ​

ParameterSymbolUnitDefaultRangeDescription
Surface AreaAm²--Tank surface area
DepthHm3.52.5-4.5Side water depth
Max Settling Velocityv₀m/h10.05.0-20.0Maximum settling velocity
Max Rising Velocityv₀'m/h0.50.0-2.0Maximum rising velocity (density currents)
Hindered ParameterrₕL/g0.50.3-0.8Hindered zone parameter
Flocculent ParameterrₚL/g2.01.0-3.0Flocculent zone parameter
Particle Diameterd_pmm0.10.01-1.0Representative particle diameter
Particle Densityρ_pkg/m³10501020-1200Particle density
TemperatureT°C155-30Wastewater temperature

Design Criteria ​

ParameterTypical RangeNotes
Surface Overflow Rate (Avg)30-50 m³/m²/dAverage dry weather flow
Surface Overflow Rate (Peak)80-120 m³/m²/dPeak wet weather flow
Detention Time1.5-2.5 hAt average flow
Weir Loading Rate120-250 m³/m/dEffluent weir overflow
Side Water Depth3.0-4.5 mCircular or rectangular
Length to Width Ratio3:1 to 5:1Rectangular tanks only
Bottom Slope1% (circ), 2% (rect)For sludge collection
Sludge Withdrawal Rate0.5-1.5 m³/m²/hPrevents septicity
Scum RemovalManual or mechanicalBeach or flights

Worked Examples ​

Example 1: Basic Mode Calculation - Municipal WWTP ​

Given:

  • Influent flow: 10,000 m³/d
  • Influent TSS: 250 mg/L
  • Influent BOD₅: 200 mg/L
  • Influent COD: 450 mg/L
  • TSS removal efficiency: 60%
  • BOD removal efficiency: 30%
  • COD removal efficiency: 30%
  • Primary sludge concentration: 4%

Calculate: Effluent characteristics and sludge production

  1. Effluent TSS:

    • $\text{TSS}_{out} = 250 \times (1 - 0.60) = 250 \times 0.40 = 100 \text{ mg/L}$
  2. Effluent BOD:

    • $\text{BOD}_{out} = 200 \times (1 - 0.30) = 200 \times 0.70 = 140 \text{ mg/L}$
  3. Effluent COD:

    • $\text{COD}_{out} = 450 \times (1 - 0.30) = 450 \times 0.70 = 315 \text{ mg/L}$
  4. TSS removed (mass):

    • $\text{TSS removed} = 10,000 \times (250 - 100) / 1000 = 10,000 \times 150 / 1000 = 1,500 \text{ kg/d}$
  5. Primary sludge volume:

    • $V_{sludge} = \frac{1,500}{1000 \times 0.04} = \frac{1,500}{40} = 37.5 \text{ m³/d}$

Solution:

  • Effluent TSS: 100 mg/L
  • Effluent BOD₅: 140 mg/L
  • Effluent COD: 315 mg/L
  • Primary sludge production: 37.5 m³/d at 4% solids (1,500 kg dry solids/d)

Example 2: Advanced Mode - Overflow Rate Sizing ​

Given:

  • Average flow: 15,000 m³/d
  • Peak flow: 45,000 m³/d
  • Target average overflow rate: 40 m³/m²/d
  • Maximum peak overflow rate: 100 m³/m²/d

Calculate: Required surface area and tank dimensions

  1. Surface area for average flow:

    • $A_{avg} = \frac{Q_{avg}}{\text{SOR}_{avg}} = \frac{15,000}{40} = 375 \text{ m²}$
  2. Surface area for peak flow:

    • $A_{peak} = \frac{Q_{peak}}{\text{SOR}_{peak}} = \frac{45,000}{100} = 450 \text{ m²}$
  3. Required surface area (governing):

    • $A_{required} = \max(375, 450) = 450 \text{ m²}$
  4. Circular tank diameter:

    • $A = \frac{\pi D^2}{4}$
    • $D = \sqrt{\frac{4A}{\pi}} = \sqrt{\frac{4 \times 450}{\pi}} = \sqrt{573} = 23.9 \text{ m}$
    • Use $D = 24 \text{ m}$ (actual area = 452 m²)
  5. Detention time at average flow (H = 3.5m):

    • $V = A \times H = 452 \times 3.5 = 1,582 \text{ m³}$
    • $\theta = \frac{V}{Q_{avg}} = \frac{1,582}{15,000/24} = \frac{1,582}{625} = 2.53 \text{ hours}$

Solution:

  • Required surface area: 450 m²
  • Tank diameter: 24 m (circular)
  • Detention time: 2.53 hours (at average flow)
  • Actual average SOR: 33.2 m³/m²/d
  • Actual peak SOR: 99.6 m³/m²/d

Example 3: Advanced Mode - Settling Velocity Removal ​

Given:

  • Flow rate: 20,000 m³/d
  • Surface area: 500 m²
  • Particle settling velocity: 0.5 m/h (from settling column tests)

Calculate: Theoretical removal efficiency

  1. Overflow rate:

    • $v_{s0} = \frac{Q}{A} = \frac{20,000/24}{500} = \frac{833.3}{500} = 1.67 \text{ m/h}$
  2. Removal efficiency (particles with v_s = 0.5 m/h):

    • For $v_s < v_{s0}$: Partial removal = $\frac{v_s}{v_{s0}}$
    • $\eta = \frac{0.5}{1.67} = 0.30 = 30%$
  3. For complete removal of these particles, required area:

    • $A_{req} = \frac{Q}{v_s} = \frac{833.3}{0.5} = 1,667 \text{ m²}$

Solution:

  • Overflow rate: 1.67 m/h
  • Theoretical removal: 30% of particles with v_s = 0.5 m/h
  • To achieve 100% removal of these particles: 1,667 m² required

Assumptions and Limitations ​

  • Assumes ideal settling conditions (quiescent, uniform flow distribution)
  • Does not account for short-circuiting, wind effects, or density currents
  • Neglects temperature effects on settling velocity and viscosity
  • Basic mode uses empirical efficiencies that vary with wastewater characteristics
  • Advanced mode requires settling velocity data from jar or column tests
  • Does not model biological activity or septic conditions in sludge blanket
  • Assumes steady-state operation (not applicable to storm events)
  • Particle size distribution must be known for accurate advanced calculations
  • Does not account for effluent weir hydraulics affecting flow distribution

Troubleshooting ​

IssuePossible CauseSolution
Low TSS removal (<50%)Hydraulic overloadReduce flow, add tankage, or check flow distribution
Rising sludge, septic odorsSludge blanket too thick, septicityIncrease sludge withdrawal frequency
Effluent turbidityHigh overflow rate at weirsReduce weir loading, add weir length
Excessive scum buildupInsufficient skimmingIncrease skimmer frequency or add mechanisms
High sludge volumeLow sludge concentrationIncrease withdrawal rate, check scraper operation
Poor flow distributionInlet baffle issuesInspect and repair inlet baffles/energy dissipators
Carry-over of solidsWind effectsAdd baffles or wind screens
Short-circuitingDead zones in tankModify baffling, check mixer operation

References ​

  1. Metcalf & Eddy (2014). Wastewater Engineering: Treatment and Resource Recovery, 5th Edition, McGraw-Hill.
  2. Water Environment Federation (2018). Design of Water Resource Recovery Facilities, Manual of Practice No. 8, 6th Edition.
  3. Tchobanoglous, G., Stensel, H.D., Tsuchihashi, R., and Burton, F. (2014). Wastewater Engineering: Treatment and Resource Recovery, 5th Edition.
  4. Camp, T.R. (1946). "Sedimentation and the Design of Settling Tanks," Transactions ASCE, 111:895-958.
  5. Hazen, A. (1904). "On Sedimentation," Transactions ASCE, 53:45-71.
  6. Takács, I., Patry, G.G., and Nolasco, D. (1991). "A Dynamic Model of the Clarification-Thickening Process," Water Research, 25(10):1263-1271.
  7. Fair, G.M., Geyer, J.C., and Okun, D.A. (1968). Water and Wastewater Engineering, Volume 2, Wiley.

Model Implementation ​

TypeScript Model Location: backend/models/processes/PrimaryClarifier.ts

Key Methods:

  • calculateBasic() - Efficiency-based removal calculations
  • calculateAdvanced() - Overflow rate and settling velocity calculations
  • validate() - Parameter range validation
  • estimateSludgeProduction() - Sludge mass and volume calculations

Change Log ​

DateVersionChanges
2025-12-301.0Initial documentation with basic and advanced modes